Base | Representation |
---|---|
bin | 11000101011100101… |
… | …10101101000111011 |
3 | 1021012110020200220101 |
4 | 30111302311220323 |
5 | 204114120102311 |
6 | 10030501140231 |
7 | 646234551034 |
oct | 142562655073 |
9 | 37173220811 |
10 | 13250550331 |
11 | 568a654647 |
12 | 26996ba677 |
13 | 1332277a35 |
14 | 8d9b49a8b |
15 | 528443ec1 |
hex | 315cb5a3b |
13250550331 has 2 divisors, whose sum is σ = 13250550332. Its totient is φ = 13250550330.
The previous prime is 13250550241. The next prime is 13250550347. The reversal of 13250550331 is 13305505231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13250550331 - 215 = 13250517563 is a prime.
It is a super-2 number, since 2×132505503312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13250550331.
It is not a weakly prime, because it can be changed into another prime (13250550361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625275165 + 6625275166.
It is an arithmetic number, because the mean of its divisors is an integer number (6625275166).
Almost surely, 213250550331 is an apocalyptic number.
13250550331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13250550331 is an equidigital number, since it uses as much as digits as its factorization.
13250550331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6750, while the sum is 28.
The spelling of 13250550331 in words is "thirteen billion, two hundred fifty million, five hundred fifty thousand, three hundred thirty-one".
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