Base | Representation |
---|---|
bin | 11000101011100101… |
… | …10101100111100001 |
3 | 1021012110020200210001 |
4 | 30111302311213201 |
5 | 204114120101431 |
6 | 10030501140001 |
7 | 646234550545 |
oct | 142562654741 |
9 | 37173220701 |
10 | 13250550241 |
11 | 568a654575 |
12 | 26996ba601 |
13 | 1332277996 |
14 | 8d9b49a25 |
15 | 528443e61 |
hex | 315cb59e1 |
13250550241 has 2 divisors, whose sum is σ = 13250550242. Its totient is φ = 13250550240.
The previous prime is 13250550151. The next prime is 13250550331. The reversal of 13250550241 is 14205505231.
It is a balanced prime because it is at equal distance from previous prime (13250550151) and next prime (13250550331).
It can be written as a sum of positive squares in only one way, i.e., 11603813841 + 1646736400 = 107721^2 + 40580^2 .
It is a cyclic number.
It is not a de Polignac number, because 13250550241 - 225 = 13216995809 is a prime.
It is not a weakly prime, because it can be changed into another prime (13250560241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625275120 + 6625275121.
It is an arithmetic number, because the mean of its divisors is an integer number (6625275121).
Almost surely, 213250550241 is an apocalyptic number.
It is an amenable number.
13250550241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13250550241 is an equidigital number, since it uses as much as digits as its factorization.
13250550241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 28.
The spelling of 13250550241 in words is "thirteen billion, two hundred fifty million, five hundred fifty thousand, two hundred forty-one".
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