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13250584133 is a prime number
BaseRepresentation
bin11000101011100101…
…11101111001000101
31021012110022102021022
430111302331321011
5204114122143013
610030502000525
7646235051423
oct142562757105
937173272238
1013250584133
11568a677a86
122699716145
13133228a237
148d9b58113
1552844e008
hex315cbde45

13250584133 has 2 divisors, whose sum is σ = 13250584134. Its totient is φ = 13250584132.

The previous prime is 13250584099. The next prime is 13250584183. The reversal of 13250584133 is 33148505231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7814913604 + 5435670529 = 88402^2 + 73727^2 .

It is a cyclic number.

It is not a de Polignac number, because 13250584133 - 26 = 13250584069 is a prime.

It is a super-2 number, since 2×132505841332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13250584093 and 13250584102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13250584183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625292066 + 6625292067.

It is an arithmetic number, because the mean of its divisors is an integer number (6625292067).

Almost surely, 213250584133 is an apocalyptic number.

It is an amenable number.

13250584133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13250584133 is an equidigital number, since it uses as much as digits as its factorization.

13250584133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 13250584133 in words is "thirteen billion, two hundred fifty million, five hundred eighty-four thousand, one hundred thirty-three".