Base | Representation |
---|---|
bin | 1100000011010010100110… |
… | …0100010111011010010101 |
3 | 1201220202022002011110221211 |
4 | 3000310221210113122111 |
5 | 3214044333401211333 |
6 | 44103135140541421 |
7 | 2535220664301646 |
oct | 300645144273225 |
9 | 51822262143854 |
10 | 13250671507093 |
11 | 424963a692189 |
12 | 15a009b0b1871 |
13 | 7516c0bbb687 |
14 | 33b49bab56cd |
15 | 17ea313e5ecd |
hex | c0d29917695 |
13250671507093 has 2 divisors, whose sum is σ = 13250671507094. Its totient is φ = 13250671507092.
The previous prime is 13250671507049. The next prime is 13250671507103. The reversal of 13250671507093 is 39070517605231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9144346177444 + 4106325329649 = 3023962^2 + 2026407^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13250671507093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13250671607093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625335753546 + 6625335753547.
It is an arithmetic number, because the mean of its divisors is an integer number (6625335753547).
Almost surely, 213250671507093 is an apocalyptic number.
It is an amenable number.
13250671507093 is a deficient number, since it is larger than the sum of its proper divisors (1).
13250671507093 is an equidigital number, since it uses as much as digits as its factorization.
13250671507093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1190700, while the sum is 49.
The spelling of 13250671507093 in words is "thirteen trillion, two hundred fifty billion, six hundred seventy-one million, five hundred seven thousand, ninety-three".
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