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13251143022133 is a prime number
BaseRepresentation
bin1100000011010100010110…
…1011000011011000110101
31201220210111221101220222211
43000311011223003120311
53214101320103202013
644103254023053421
72535235451150242
oct300650553033065
951823457356884
1013251143022133
114249861863435
1215a01b0ba1271
137517677ac263
1433b5045745c9
1517ea5c9d423d
hexc0d45ac3635

13251143022133 has 2 divisors, whose sum is σ = 13251143022134. Its totient is φ = 13251143022132.

The previous prime is 13251143022119. The next prime is 13251143022167. The reversal of 13251143022133 is 33122034115231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6833194665444 + 6417948356689 = 2614038^2 + 2533367^2 .

It is a cyclic number.

It is not a de Polignac number, because 13251143022133 - 29 = 13251143021621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13251143022095 and 13251143022104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13251143029133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625571511066 + 6625571511067.

It is an arithmetic number, because the mean of its divisors is an integer number (6625571511067).

Almost surely, 213251143022133 is an apocalyptic number.

It is an amenable number.

13251143022133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13251143022133 is an equidigital number, since it uses as much as digits as its factorization.

13251143022133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 13251143022133 its reverse (33122034115231), we get a palindrome (46373177137364).

The spelling of 13251143022133 in words is "thirteen trillion, two hundred fifty-one billion, one hundred forty-three million, twenty-two thousand, one hundred thirty-three".