Base | Representation |
---|---|
bin | 10011010010000111011… |
… | …001011000001100010011 |
3 | 11200200100222220002012221 |
4 | 103102013121120030103 |
5 | 133202322101112034 |
6 | 2452430304401511 |
7 | 164510513640025 |
oct | 23220731301423 |
9 | 4620328802187 |
10 | 1325121504019 |
11 | 470a875a7a65 |
12 | 194998616297 |
13 | 97c5c863311 |
14 | 481c9b20015 |
15 | 247095e8bb4 |
hex | 13487658313 |
1325121504019 has 2 divisors, whose sum is σ = 1325121504020. Its totient is φ = 1325121504018.
The previous prime is 1325121504013. The next prime is 1325121504127. The reversal of 1325121504019 is 9104051215231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1325121504019 - 219 = 1325120979731 is a prime.
It is a super-2 number, since 2×13251215040192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1325121504013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662560752009 + 662560752010.
It is an arithmetic number, because the mean of its divisors is an integer number (662560752010).
Almost surely, 21325121504019 is an apocalyptic number.
1325121504019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325121504019 is an equidigital number, since it uses as much as digits as its factorization.
1325121504019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 34.
The spelling of 1325121504019 in words is "one trillion, three hundred twenty-five billion, one hundred twenty-one million, five hundred four thousand, nineteen".
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