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132517639 is a prime number
BaseRepresentation
bin1111110011000…
…00111100000111
3100020100121000201
413321200330013
5232411031024
621052151331
73166244542
oct771407407
9306317021
10132517639
1168891511
1238468547
13215ba707
1413857859
15b979744
hex7e60f07

132517639 has 2 divisors, whose sum is σ = 132517640. Its totient is φ = 132517638.

The previous prime is 132517607. The next prime is 132517663. The reversal of 132517639 is 936715231.

It is a strong prime.

It is an emirp because it is prime and its reverse (936715231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132517639 - 25 = 132517607 is a prime.

It is a super-2 number, since 2×1325176392 = 35121849292268642, which contains 22 as substring.

It is a zygodrome in base 2.

It is a junction number, because it is equal to n+sod(n) for n = 132517598 and 132517607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132517439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66258819 + 66258820.

It is an arithmetic number, because the mean of its divisors is an integer number (66258820).

Almost surely, 2132517639 is an apocalyptic number.

132517639 is a deficient number, since it is larger than the sum of its proper divisors (1).

132517639 is an equidigital number, since it uses as much as digits as its factorization.

132517639 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34020, while the sum is 37.

The square root of 132517639 is about 11511.6305969224. The cubic root of 132517639 is about 509.8290327866.

The spelling of 132517639 in words is "one hundred thirty-two million, five hundred seventeen thousand, six hundred thirty-nine".