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1325211243049 is a prime number
BaseRepresentation
bin10011010010001100101…
…111101101001000101001
311200200121020202022000201
4103102030233231020221
5133203013034234144
62452443232032201
7164512653464611
oct23221457551051
94620536668021
101325211243049
11471023220251
12194a02692661
1397c75323535
14481d79dda41
15247124231d4
hex1348cbed229

1325211243049 has 2 divisors, whose sum is σ = 1325211243050. Its totient is φ = 1325211243048.

The previous prime is 1325211243011. The next prime is 1325211243113. The reversal of 1325211243049 is 9403421125231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1194141901824 + 131069341225 = 1092768^2 + 362035^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1325211243049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1325211242999 and 1325211243017.

It is not a weakly prime, because it can be changed into another prime (1325211243949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662605621524 + 662605621525.

It is an arithmetic number, because the mean of its divisors is an integer number (662605621525).

Almost surely, 21325211243049 is an apocalyptic number.

It is an amenable number.

1325211243049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325211243049 is an equidigital number, since it uses as much as digits as its factorization.

1325211243049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 1325211243049 in words is "one trillion, three hundred twenty-five billion, two hundred eleven million, two hundred forty-three thousand, forty-nine".