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1325211243050 = 25226504224861
BaseRepresentation
bin10011010010001100101…
…111101101001000101010
311200200121020202022000202
4103102030233231020222
5133203013034234200
62452443232032202
7164512653464612
oct23221457551052
94620536668022
101325211243050
11471023220252
12194a02692662
1397c75323536
14481d79dda42
15247124231d5
hex1348cbed22a

1325211243050 has 12 divisors (see below), whose sum is σ = 2464892912166. Its totient is φ = 530084497200.

The previous prime is 1325211243049. The next prime is 1325211243113. The reversal of 1325211243050 is 503421125231.

It can be written as a sum of positive squares in 3 ways, for example, as 1247034523849 + 78176719201 = 1116707^2 + 279601^2 .

It is a super-2 number, since 2×13252112430502 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13252112381 + ... + 13252112480.

Almost surely, 21325211243050 is an apocalyptic number.

1325211243050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1325211243050 is a deficient number, since it is larger than the sum of its proper divisors (1139681669116).

1325211243050 is a wasteful number, since it uses less digits than its factorization.

1325211243050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26504224873 (or 26504224868 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1325211243050 its reverse (503421125231), we get a palindrome (1828632368281).

The spelling of 1325211243050 in words is "one trillion, three hundred twenty-five billion, two hundred eleven million, two hundred forty-three thousand, fifty".

Divisors: 1 2 5 10 25 50 26504224861 53008449722 132521124305 265042248610 662605621525 1325211243050