Base | Representation |
---|---|
bin | 11000101011110001… |
… | …10110001101100101 |
3 | 1021012120012201200111 |
4 | 30111320312031211 |
5 | 204120021004131 |
6 | 10030555013021 |
7 | 646254131344 |
oct | 142570661545 |
9 | 37176181614 |
10 | 13252125541 |
11 | 5690530076 |
12 | 269a13a171 |
13 | 13326a9a05 |
14 | 8da039b5b |
15 | 528655ab1 |
hex | 315e36365 |
13252125541 has 2 divisors, whose sum is σ = 13252125542. Its totient is φ = 13252125540.
The previous prime is 13252125527. The next prime is 13252125577. The reversal of 13252125541 is 14552125231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10454244516 + 2797881025 = 102246^2 + 52895^2 .
It is a cyclic number.
It is not a de Polignac number, because 13252125541 - 213 = 13252117349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13252126541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626062770 + 6626062771.
It is an arithmetic number, because the mean of its divisors is an integer number (6626062771).
Almost surely, 213252125541 is an apocalyptic number.
It is an amenable number.
13252125541 is a deficient number, since it is larger than the sum of its proper divisors (1).
13252125541 is an equidigital number, since it uses as much as digits as its factorization.
13252125541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12000, while the sum is 31.
The spelling of 13252125541 in words is "thirteen billion, two hundred fifty-two million, one hundred twenty-five thousand, five hundred forty-one".
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