Base | Representation |
---|---|
bin | 10011010010001110101… |
… | …010001100110011100101 |
3 | 11200200200111011201102211 |
4 | 103102032222030303211 |
5 | 133203044244314331 |
6 | 2452450340203421 |
7 | 164513523435544 |
oct | 23221652146345 |
9 | 4620614151384 |
10 | 1325243354341 |
11 | 47103a362a05 |
12 | 194a11399571 |
13 | 97c7bb874ba |
14 | 481dbd9c15b |
15 | 247151678b1 |
hex | 1348ea8cce5 |
1325243354341 has 2 divisors, whose sum is σ = 1325243354342. Its totient is φ = 1325243354340.
The previous prime is 1325243354333. The next prime is 1325243354359. The reversal of 1325243354341 is 1434533425231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 833906844225 + 491336510116 = 913185^2 + 700954^2 .
It is a cyclic number.
It is not a de Polignac number, because 1325243354341 - 23 = 1325243354333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1325243354294 and 1325243354303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1325243354381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662621677170 + 662621677171.
It is an arithmetic number, because the mean of its divisors is an integer number (662621677171).
Almost surely, 21325243354341 is an apocalyptic number.
It is an amenable number.
1325243354341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325243354341 is an equidigital number, since it uses as much as digits as its factorization.
1325243354341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 518400, while the sum is 40.
Adding to 1325243354341 its reverse (1434533425231), we get a palindrome (2759776779572).
The spelling of 1325243354341 in words is "one trillion, three hundred twenty-five billion, two hundred forty-three million, three hundred fifty-four thousand, three hundred forty-one".
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