Base | Representation |
---|---|
bin | 10011010010001110110… |
… | …001000100100010101111 |
3 | 11200200200121120020011112 |
4 | 103102032301010202233 |
5 | 133203100224434003 |
6 | 2452450442542235 |
7 | 164513544650003 |
oct | 23221661044257 |
9 | 4620617506145 |
10 | 1325245155503 |
11 | 471040383175 |
12 | 194a11b0797b |
13 | 97c7c368289 |
14 | 481dc30a703 |
15 | 247153c13d8 |
hex | 1348ec448af |
1325245155503 has 2 divisors, whose sum is σ = 1325245155504. Its totient is φ = 1325245155502.
The previous prime is 1325245155491. The next prime is 1325245155517. The reversal of 1325245155503 is 3055515425231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1325245155503 - 26 = 1325245155439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1325245155203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662622577751 + 662622577752.
It is an arithmetic number, because the mean of its divisors is an integer number (662622577752).
Almost surely, 21325245155503 is an apocalyptic number.
1325245155503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325245155503 is an equidigital number, since it uses as much as digits as its factorization.
1325245155503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 450000, while the sum is 41.
The spelling of 1325245155503 in words is "one trillion, three hundred twenty-five billion, two hundred forty-five million, one hundred fifty-five thousand, five hundred three".
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