Base | Representation |
---|---|
bin | 11000101011110100… |
… | …10101101001010111 |
3 | 1021012120221120220012 |
4 | 30111322111221113 |
5 | 204120121011224 |
6 | 10031011230435 |
7 | 646260350111 |
oct | 142572255127 |
9 | 37176846805 |
10 | 13252516439 |
11 | 5690777828 |
12 | 269a2a841b |
13 | 13327b5906 |
14 | 8da0dc3b1 |
15 | 5286d180e |
hex | 315e95a57 |
13252516439 has 2 divisors, whose sum is σ = 13252516440. Its totient is φ = 13252516438.
The previous prime is 13252516391. The next prime is 13252516499. The reversal of 13252516439 is 93461525231.
It is a weak prime.
It is an emirp because it is prime and its reverse (93461525231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13252516439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13252516396 and 13252516405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13252516499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626258219 + 6626258220.
It is an arithmetic number, because the mean of its divisors is an integer number (6626258220).
Almost surely, 213252516439 is an apocalyptic number.
13252516439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13252516439 is an equidigital number, since it uses as much as digits as its factorization.
13252516439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 194400, while the sum is 41.
The spelling of 13252516439 in words is "thirteen billion, two hundred fifty-two million, five hundred sixteen thousand, four hundred thirty-nine".
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