Base | Representation |
---|---|
bin | 10011010010010001011… |
… | …110001100110100001111 |
3 | 11200200210202222000102001 |
4 | 103102101132030310033 |
5 | 133203143334242203 |
6 | 2452455143413131 |
7 | 164514635503132 |
oct | 23222136146417 |
9 | 4620722860361 |
10 | 1325290540303 |
11 | 471063a61474 |
12 | 194a251541a7 |
13 | 97c88898aa2 |
14 | 48204362219 |
15 | 2471938891d |
hex | 1349178cd0f |
1325290540303 has 2 divisors, whose sum is σ = 1325290540304. Its totient is φ = 1325290540302.
The previous prime is 1325290540201. The next prime is 1325290540331. The reversal of 1325290540303 is 3030450925231.
It is a strong prime.
It is an emirp because it is prime and its reverse (3030450925231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1325290540303 - 229 = 1324753669391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1325290541303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662645270151 + 662645270152.
It is an arithmetic number, because the mean of its divisors is an integer number (662645270152).
Almost surely, 21325290540303 is an apocalyptic number.
1325290540303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325290540303 is an equidigital number, since it uses as much as digits as its factorization.
1325290540303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 1325290540303 in words is "one trillion, three hundred twenty-five billion, two hundred ninety million, five hundred forty thousand, three hundred three".
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