Base | Representation |
---|---|
bin | 111101101101101101… |
… | …1011001001010001111 |
3 | 110200002021100101202102 |
4 | 1323123123121022033 |
5 | 4132410241111002 |
6 | 140514510345315 |
7 | 12401140620233 |
oct | 1733333311217 |
9 | 420067311672 |
10 | 132530410127 |
11 | 51229a63775 |
12 | 218281bb23b |
13 | c6611c082b |
14 | 65b35945c3 |
15 | 36aa099a02 |
hex | 1edb6d928f |
132530410127 has 2 divisors, whose sum is σ = 132530410128. Its totient is φ = 132530410126.
The previous prime is 132530410121. The next prime is 132530410157. The reversal of 132530410127 is 721014035231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132530410127 - 26 = 132530410063 is a prime.
It is a super-2 number, since 2×1325304101272 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132530410127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132530410121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66265205063 + 66265205064.
It is an arithmetic number, because the mean of its divisors is an integer number (66265205064).
Almost surely, 2132530410127 is an apocalyptic number.
132530410127 is a deficient number, since it is larger than the sum of its proper divisors (1).
132530410127 is an equidigital number, since it uses as much as digits as its factorization.
132530410127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 132530410127 its reverse (721014035231), we get a palindrome (853544445358).
The spelling of 132530410127 in words is "one hundred thirty-two billion, five hundred thirty million, four hundred ten thousand, one hundred twenty-seven".
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