Base | Representation |
---|---|
bin | 111101101101101111… |
… | …0111110101000100011 |
3 | 110200002100010011002102 |
4 | 1323123132332220203 |
5 | 4132411011200201 |
6 | 140514542441015 |
7 | 12401151613442 |
oct | 1733336765043 |
9 | 420070104072 |
10 | 132531350051 |
11 | 5122a545971 |
12 | 2182859316b |
13 | c66145c5b9 |
14 | 65b375ad59 |
15 | 36aa1d326b |
hex | 1edb7bea23 |
132531350051 has 2 divisors, whose sum is σ = 132531350052. Its totient is φ = 132531350050.
The previous prime is 132531350041. The next prime is 132531350057. The reversal of 132531350051 is 150053135231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132531350051 - 26 = 132531349987 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132531349996 and 132531350023.
It is not a weakly prime, because it can be changed into another prime (132531350057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66265675025 + 66265675026.
It is an arithmetic number, because the mean of its divisors is an integer number (66265675026).
Almost surely, 2132531350051 is an apocalyptic number.
132531350051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132531350051 is an equidigital number, since it uses as much as digits as its factorization.
132531350051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6750, while the sum is 29.
Adding to 132531350051 its reverse (150053135231), we get a palindrome (282584485282).
The spelling of 132531350051 in words is "one hundred thirty-two billion, five hundred thirty-one million, three hundred fifty thousand, fifty-one".
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