Base | Representation |
---|---|
bin | 1100000011011100100101… |
… | …1110001100001111101010 |
3 | 1201221000020001012120211211 |
4 | 3000313021132030033222 |
5 | 3214120332141234200 |
6 | 44104301253143334 |
7 | 2535344321212405 |
oct | 300671136141752 |
9 | 51830201176754 |
10 | 13253354243050 |
11 | 424a796a57439 |
12 | 15a070962ab4a |
13 | 751a2a93c0bc |
14 | 33b6740d2d3c |
15 | 17eb3bbbaaba |
hex | c0dc978c3ea |
13253354243050 has 48 divisors (see below), whose sum is σ = 24990258646080. Its totient is φ = 5228441965440.
The previous prime is 13253354242969. The next prime is 13253354243081. The reversal of 13253354243050 is 5034245335231.
13253354243050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13253354242994 and 13253354243012.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 76779139 + ... + 76951561.
It is an arithmetic number, because the mean of its divisors is an integer number (520630388460).
Almost surely, 213253354243050 is an apocalyptic number.
13253354243050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13253354243050 is a deficient number, since it is larger than the sum of its proper divisors (11736904403030).
13253354243050 is a wasteful number, since it uses less digits than its factorization.
13253354243050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193567 (or 193562 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 13253354243050 its reverse (5034245335231), we get a palindrome (18287599578281).
The spelling of 13253354243050 in words is "thirteen trillion, two hundred fifty-three billion, three hundred fifty-four million, two hundred forty-three thousand, fifty".
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