13253404139 has 2 divisors, whose sum is σ = 13253404140. Its totient is φ = 13253404138.

The previous prime is 13253404121. The next prime is 13253404141. The reversal of 13253404139 is 93140435231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13253404139 is a prime.

Together with 13253404141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13253404099 and 13253404108.

It is not a weakly prime, because it can be changed into another prime (13253404189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626702069 + 6626702070.

It is an arithmetic number, because the mean of its divisors is an integer number (6626702070).

Almost surely, 2^13253404139 is an apocalyptic number.

13253404139 is a deficient number, since it is larger than the sum of its proper divisors (1).

13253404139 is an equidigital number, since it uses as much as digits as its factorization.

13253404139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

The spelling of 13253404139 in words is "thirteen billion, two hundred fifty-three million, four hundred four thousand, one hundred thirty-nine".