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1325408093 is a prime number
BaseRepresentation
bin100111100000000…
…0001111101011101
310102100222201002122
41033000001331131
510203301024333
6335304032325
744562532352
oct11700017535
93370881078
101325408093
11620181799
1230ba626a5
13181792b59
14c8056629
157b55d798
hex4f001f5d

1325408093 has 2 divisors, whose sum is σ = 1325408094. Its totient is φ = 1325408092.

The previous prime is 1325408059. The next prime is 1325408171. The reversal of 1325408093 is 3908045231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 946054564 + 379353529 = 30758^2 + 19477^2 .

It is an emirp because it is prime and its reverse (3908045231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1325408093 is a prime.

It is a super-2 number, since 2×13254080932 = 3513413225979793298, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1325408053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662704046 + 662704047.

It is an arithmetic number, because the mean of its divisors is an integer number (662704047).

Almost surely, 21325408093 is an apocalyptic number.

It is an amenable number.

1325408093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325408093 is an equidigital number, since it uses as much as digits as its factorization.

1325408093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

The square root of 1325408093 is about 36406.1546033085. The cubic root of 1325408093 is about 1098.4573673857.

The spelling of 1325408093 in words is "one billion, three hundred twenty-five million, four hundred eight thousand, ninety-three".