Base | Representation |
---|---|
bin | 11110001000101111111011… |
… | …010101101101111011111011 |
3 | 122101021221122120010021022211 |
4 | 132020233323111231323323 |
5 | 114333034232303433114 |
6 | 1145521122521155551 |
7 | 36626613332656636 |
oct | 3610577325557373 |
9 | 571257576107284 |
10 | 132542612561659 |
11 | 39261008459813 |
12 | 12a4779092bbb7 |
13 | 58c593a36a341 |
14 | 24a314d3d0c1d |
15 | 104cb0e2036c4 |
hex | 788bfb56defb |
132542612561659 has 2 divisors, whose sum is σ = 132542612561660. Its totient is φ = 132542612561658.
The previous prime is 132542612561657. The next prime is 132542612561663. The reversal of 132542612561659 is 956165216245231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132542612561659 - 21 = 132542612561657 is a prime.
It is a super-2 number, since 2×1325426125616592 (a number of 29 digits) contains 22 as substring.
Together with 132542612561657, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132542612561657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66271306280829 + 66271306280830.
It is an arithmetic number, because the mean of its divisors is an integer number (66271306280830).
Almost surely, 2132542612561659 is an apocalyptic number.
132542612561659 is a deficient number, since it is larger than the sum of its proper divisors (1).
132542612561659 is an equidigital number, since it uses as much as digits as its factorization.
132542612561659 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23328000, while the sum is 58.
The spelling of 132542612561659 in words is "one hundred thirty-two trillion, five hundred forty-two billion, six hundred twelve million, five hundred sixty-one thousand, six hundred fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •