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1325440514257 is a prime number
BaseRepresentation
bin10011010010011010011…
…010010011100011010001
311200201012020011110222221
4103102122122103203101
5133204000232424012
62452522102101041
7164521436324026
oct23223232234321
94621166143887
101325440514257
11471130686092
12194a6741a781
1397cb0988b82
144821a24154d
1524727610507
hex1349a6938d1

1325440514257 has 2 divisors, whose sum is σ = 1325440514258. Its totient is φ = 1325440514256.

The previous prime is 1325440514239. The next prime is 1325440514347. The reversal of 1325440514257 is 7524150445231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1150211205441 + 175229308816 = 1072479^2 + 418604^2 .

It is a cyclic number.

It is not a de Polignac number, because 1325440514257 - 223 = 1325432125649 is a prime.

It is not a weakly prime, because it can be changed into another prime (1325440554257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662720257128 + 662720257129.

It is an arithmetic number, because the mean of its divisors is an integer number (662720257129).

Almost surely, 21325440514257 is an apocalyptic number.

It is an amenable number.

1325440514257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325440514257 is an equidigital number, since it uses as much as digits as its factorization.

1325440514257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672000, while the sum is 43.

Adding to 1325440514257 its reverse (7524150445231), we get a palindrome (8849590959488).

The spelling of 1325440514257 in words is "one trillion, three hundred twenty-five billion, four hundred forty million, five hundred fourteen thousand, two hundred fifty-seven".