Base | Representation |
---|---|
bin | 10011010010011010011… |
… | …010010011100100101011 |
3 | 11200201012020011111010021 |
4 | 103102122122103210223 |
5 | 133204000232424342 |
6 | 2452522102101311 |
7 | 164521436324215 |
oct | 23223232234453 |
9 | 4621166144107 |
10 | 1325440514347 |
11 | 471130686164 |
12 | 194a6741a837 |
13 | 97cb0988c21 |
14 | 4821a2415b5 |
15 | 24727610567 |
hex | 1349a69392b |
1325440514347 has 2 divisors, whose sum is σ = 1325440514348. Its totient is φ = 1325440514346.
The previous prime is 1325440514257. The next prime is 1325440514393. The reversal of 1325440514347 is 7434150445231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1325440514347 - 27 = 1325440514219 is a prime.
It is not a weakly prime, because it can be changed into another prime (1325440517347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662720257173 + 662720257174.
It is an arithmetic number, because the mean of its divisors is an integer number (662720257174).
Almost surely, 21325440514347 is an apocalyptic number.
1325440514347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325440514347 is an equidigital number, since it uses as much as digits as its factorization.
1325440514347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 806400, while the sum is 43.
Adding to 1325440514347 its reverse (7434150445231), we get a palindrome (8759590959578).
The spelling of 1325440514347 in words is "one trillion, three hundred twenty-five billion, four hundred forty million, five hundred fourteen thousand, three hundred forty-seven".
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