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132557081004941 is a prime number
BaseRepresentation
bin11110001000111101011001…
…101110011100101110001101
3122101100022222220001100021112
4132020331121232130232031
5114333303400214124231
61145531514330141405
736630635016501215
oct3610753156345615
9571308886040245
10132557081004941
113926716252035a
1212a4a54a281865
1358c7104a32898
1424a3b22ba7245
15104d1a951992b
hex788f59b9cb8d

132557081004941 has 2 divisors, whose sum is σ = 132557081004942. Its totient is φ = 132557081004940.

The previous prime is 132557081004889. The next prime is 132557081004977. The reversal of 132557081004941 is 149400180755231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129736542138025 + 2820538866916 = 11390195^2 + 1679446^2 .

It is a cyclic number.

It is not a de Polignac number, because 132557081004941 - 226 = 132557013896077 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132557081004941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132557081034941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66278540502470 + 66278540502471.

It is an arithmetic number, because the mean of its divisors is an integer number (66278540502471).

Almost surely, 2132557081004941 is an apocalyptic number.

It is an amenable number.

132557081004941 is a deficient number, since it is larger than the sum of its proper divisors (1).

132557081004941 is an equidigital number, since it uses as much as digits as its factorization.

132557081004941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 50.

The spelling of 132557081004941 in words is "one hundred thirty-two trillion, five hundred fifty-seven billion, eighty-one million, four thousand, nine hundred forty-one".