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13256024533151 is a prime number
BaseRepresentation
bin1100000011100110100010…
…1000100010100010011111
31201221021010010211101020012
43000321220220202202133
53214141314240030101
644105422242513435
72535500434255631
oct300715050424237
951837103741205
1013256024533151
1142509372a0964
1215a113396587b
13752064c2290a
1433b8489d0a51
1517ec46332bbb
hexc0e68a2289f

13256024533151 has 2 divisors, whose sum is σ = 13256024533152. Its totient is φ = 13256024533150.

The previous prime is 13256024533133. The next prime is 13256024533159. The reversal of 13256024533151 is 15133542065231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13256024533151 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13256024533099 and 13256024533108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13256024533159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6628012266575 + 6628012266576.

It is an arithmetic number, because the mean of its divisors is an integer number (6628012266576).

Almost surely, 213256024533151 is an apocalyptic number.

13256024533151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13256024533151 is an equidigital number, since it uses as much as digits as its factorization.

13256024533151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 41.

Adding to 13256024533151 its reverse (15133542065231), we get a palindrome (28389566598382).

The spelling of 13256024533151 in words is "thirteen trillion, two hundred fifty-six billion, twenty-four million, five hundred thirty-three thousand, one hundred fifty-one".