Base | Representation |
---|---|
bin | 111101101110111010… |
… | …1000111001111010101 |
3 | 110200012002011200112112 |
4 | 1323131311013033111 |
5 | 4133001100110101 |
6 | 140522510200405 |
7 | 12402140262443 |
oct | 1733565071725 |
9 | 420162150475 |
10 | 132570706901 |
11 | 5124a787296 |
12 | 218397b3105 |
13 | c66965c489 |
14 | 65b8a83b93 |
15 | 36ad8a96bb |
hex | 1eddd473d5 |
132570706901 has 2 divisors, whose sum is σ = 132570706902. Its totient is φ = 132570706900.
The previous prime is 132570706861. The next prime is 132570707033. The reversal of 132570706901 is 109607075231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74958226225 + 57612480676 = 273785^2 + 240026^2 .
It is a cyclic number.
It is not a de Polignac number, because 132570706901 - 230 = 131496965077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132570706201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66285353450 + 66285353451.
It is an arithmetic number, because the mean of its divisors is an integer number (66285353451).
Almost surely, 2132570706901 is an apocalyptic number.
It is an amenable number.
132570706901 is a deficient number, since it is larger than the sum of its proper divisors (1).
132570706901 is an equidigital number, since it uses as much as digits as its factorization.
132570706901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 79380, while the sum is 41.
The spelling of 132570706901 in words is "one hundred thirty-two billion, five hundred seventy million, seven hundred six thousand, nine hundred one".
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