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132570707053 is a prime number
BaseRepresentation
bin111101101110111010…
…1000111010001101101
3110200012002011200202011
41323131311013101231
54133001100111203
6140522510201221
712402140263051
oct1733565072155
9420162150664
10132570707053
115124a787414
12218397b3211
13c66965c575
1465b8a83c61
1536ad8a976d
hex1eddd4746d

132570707053 has 2 divisors, whose sum is σ = 132570707054. Its totient is φ = 132570707052.

The previous prime is 132570707033. The next prime is 132570707063. The reversal of 132570707053 is 350707075231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132552061929 + 18645124 = 364077^2 + 4318^2 .

It is a cyclic number.

It is not a de Polignac number, because 132570707053 - 229 = 132033836141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132570706997 and 132570707015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132570707033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66285353526 + 66285353527.

It is an arithmetic number, because the mean of its divisors is an integer number (66285353527).

Almost surely, 2132570707053 is an apocalyptic number.

It is an amenable number.

132570707053 is a deficient number, since it is larger than the sum of its proper divisors (1).

132570707053 is an equidigital number, since it uses as much as digits as its factorization.

132570707053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 154350, while the sum is 40.

The spelling of 132570707053 in words is "one hundred thirty-two billion, five hundred seventy million, seven hundred seven thousand, fifty-three".