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13257102517 = 47282066011
BaseRepresentation
bin11000101100010111…
…10101010010110101
31021012220120120210221
430112023311102311
5204122304240032
610031253414341
7646344340441
oct142613652265
937186516727
1013257102517
11569331a37a
12269b93a3b1
131333730179
148da973821
15528cda597
hex3162f54b5

13257102517 has 4 divisors (see below), whose sum is σ = 13539168576. Its totient is φ = 12975036460.

The previous prime is 13257102511. The next prime is 13257102577. The reversal of 13257102517 is 71520175231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13257102517 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13257102511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141032959 + ... + 141033052.

It is an arithmetic number, because the mean of its divisors is an integer number (3384792144).

Almost surely, 213257102517 is an apocalyptic number.

It is an amenable number.

13257102517 is a deficient number, since it is larger than the sum of its proper divisors (282066059).

13257102517 is an equidigital number, since it uses as much as digits as its factorization.

13257102517 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282066058.

The product of its (nonzero) digits is 14700, while the sum is 34.

Adding to 13257102517 its reverse (71520175231), we get a palindrome (84777277748).

The spelling of 13257102517 in words is "thirteen billion, two hundred fifty-seven million, one hundred two thousand, five hundred seventeen".

Divisors: 1 47 282066011 13257102517