Base | Representation |
---|---|
bin | 11000101100011111… |
… | …00111001011111011 |
3 | 1021012222102220220212 |
4 | 30112033213023323 |
5 | 204123032441212 |
6 | 10031330541335 |
7 | 646355635154 |
oct | 142617471373 |
9 | 37188386825 |
10 | 13258093307 |
11 | 5693936808 |
12 | 26a013784b |
13 | 13339b9134 |
14 | 8dab5092b |
15 | 528e33e22 |
hex | 3163e72fb |
13258093307 has 2 divisors, whose sum is σ = 13258093308. Its totient is φ = 13258093306.
The previous prime is 13258093301. The next prime is 13258093309. The reversal of 13258093307 is 70339085231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13258093307 - 26 = 13258093243 is a prime.
Together with 13258093309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13258093301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6629046653 + 6629046654.
It is an arithmetic number, because the mean of its divisors is an integer number (6629046654).
Almost surely, 213258093307 is an apocalyptic number.
13258093307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13258093307 is an equidigital number, since it uses as much as digits as its factorization.
13258093307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 13258093307 in words is "thirteen billion, two hundred fifty-eight million, ninety-three thousand, three hundred seven".
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