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13260201541 = 29457248329
BaseRepresentation
bin11000101100101111…
…01001111001000101
31021020010102000212121
430112113221321011
5204124102422131
610031444045541
7646412565466
oct142627517105
937203360777
1013260201541
115695046754
1226a09938b1
131334276902
148db13cd6d
155291ed911
hex3165e9e45

13260201541 has 4 divisors (see below), whose sum is σ = 13717449900. Its totient is φ = 12802953184.

The previous prime is 13260201511. The next prime is 13260201551. The reversal of 13260201541 is 14510206231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7098736516 + 6161465025 = 84254^2 + 78495^2 .

It is a cyclic number.

It is not a de Polignac number, because 13260201541 - 211 = 13260199493 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13260201511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228624136 + ... + 228624193.

It is an arithmetic number, because the mean of its divisors is an integer number (3429362475).

Almost surely, 213260201541 is an apocalyptic number.

It is an amenable number.

13260201541 is a deficient number, since it is larger than the sum of its proper divisors (457248359).

13260201541 is an equidigital number, since it uses as much as digits as its factorization.

13260201541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 457248358.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13260201541 its reverse (14510206231), we get a palindrome (27770407772).

The spelling of 13260201541 in words is "thirteen billion, two hundred sixty million, two hundred one thousand, five hundred forty-one".

Divisors: 1 29 457248329 13260201541