Base | Representation |
---|---|
bin | 11000101100110101… |
… | …10010000101100101 |
3 | 1021020011221200200222 |
4 | 30112122302011211 |
5 | 204124310142131 |
6 | 10031513414125 |
7 | 646422552245 |
oct | 142632620545 |
9 | 37204850628 |
10 | 13261021541 |
11 | 5695556839 |
12 | 26a110a345 |
13 | 13344a2c11 |
14 | 8db2b3b25 |
15 | 52931187b |
hex | 3166b2165 |
13261021541 has 2 divisors, whose sum is σ = 13261021542. Its totient is φ = 13261021540.
The previous prime is 13261021511. The next prime is 13261021619. The reversal of 13261021541 is 14512016231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9667019041 + 3594002500 = 98321^2 + 59950^2 .
It is a cyclic number.
It is not a de Polignac number, because 13261021541 - 218 = 13260759397 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13261021541.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13261021511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6630510770 + 6630510771.
It is an arithmetic number, because the mean of its divisors is an integer number (6630510771).
Almost surely, 213261021541 is an apocalyptic number.
It is an amenable number.
13261021541 is a deficient number, since it is larger than the sum of its proper divisors (1).
13261021541 is an equidigital number, since it uses as much as digits as its factorization.
13261021541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 13261021541 its reverse (14512016231), we get a palindrome (27773037772).
The spelling of 13261021541 in words is "thirteen billion, two hundred sixty-one million, twenty-one thousand, five hundred forty-one".
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