Base | Representation |
---|---|
bin | 1100000011111001111100… |
… | …0010101010111000101011 |
3 | 1201221202120002012100211012 |
4 | 3000332133002222320223 |
5 | 3214233000433220133 |
6 | 44112043115454135 |
7 | 2536043461602041 |
oct | 300763702527053 |
9 | 51852502170735 |
10 | 13261232320043 |
11 | 4253069a1a274 |
12 | 15a2147a5734b |
13 | 7526b4b33c16 |
14 | 33bbc0500391 |
15 | 17ee4d630b48 |
hex | c0f9f0aae2b |
13261232320043 has 2 divisors, whose sum is σ = 13261232320044. Its totient is φ = 13261232320042.
The previous prime is 13261232320031. The next prime is 13261232320073. The reversal of 13261232320043 is 34002323216231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13261232320043 - 234 = 13244052450859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13261232319991 and 13261232320009.
It is not a weakly prime, because it can be changed into another prime (13261232320073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6630616160021 + 6630616160022.
It is an arithmetic number, because the mean of its divisors is an integer number (6630616160022).
Almost surely, 213261232320043 is an apocalyptic number.
13261232320043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13261232320043 is an equidigital number, since it uses as much as digits as its factorization.
13261232320043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 13261232320043 its reverse (34002323216231), we get a palindrome (47263555536274).
The spelling of 13261232320043 in words is "thirteen trillion, two hundred sixty-one billion, two hundred thirty-two million, three hundred twenty thousand, forty-three".
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