Base | Representation |
---|---|
bin | 1100000011111101110100… |
… | …1100101001111100100111 |
3 | 1201221212020202102100100011 |
4 | 3000333131030221330213 |
5 | 3214242114413000111 |
6 | 44112334410431051 |
7 | 2536111353362602 |
oct | 300773514517447 |
9 | 51855222370304 |
10 | 13262275125031 |
11 | 425355461a079 |
12 | 15a2399132487 |
13 | 75281cbaa5aa |
14 | 33bc7cbd1339 |
15 | 17eeaee6a021 |
hex | c0fdd329f27 |
13262275125031 has 2 divisors, whose sum is σ = 13262275125032. Its totient is φ = 13262275125030.
The previous prime is 13262275124999. The next prime is 13262275125083. The reversal of 13262275125031 is 13052157226231.
It is a weak prime.
It is an emirp because it is prime and its reverse (13052157226231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13262275125031 - 25 = 13262275124999 is a prime.
It is a super-2 number, since 2×132622751250312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13262275128031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6631137562515 + 6631137562516.
It is an arithmetic number, because the mean of its divisors is an integer number (6631137562516).
Almost surely, 213262275125031 is an apocalyptic number.
13262275125031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13262275125031 is an equidigital number, since it uses as much as digits as its factorization.
13262275125031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 13262275125031 in words is "thirteen trillion, two hundred sixty-two billion, two hundred seventy-five million, one hundred twenty-five thousand, thirty-one".
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