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132624054435221 is a prime number
BaseRepresentation
bin11110001001111011110001…
…101001110011110110010101
3122101120201212101101010000022
4132021323301221303312111
5114340403030413411341
61150022352143154525
736635525463324356
oct3611736151636625
9571521771333008
10132624054435221
1139292600254838
1212a5b51b5a5a45
13590051912217b
1424a707785bd2d
15104ecc9088e4b
hex789ef1a73d95

132624054435221 has 2 divisors, whose sum is σ = 132624054435222. Its totient is φ = 132624054435220.

The previous prime is 132624054435193. The next prime is 132624054435269. The reversal of 132624054435221 is 122534450426231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111688753524100 + 20935300911121 = 10568290^2 + 4575511^2 .

It is an emirp because it is prime and its reverse (122534450426231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132624054435221 - 218 = 132624054173077 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132624054438221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66312027217610 + 66312027217611.

It is an arithmetic number, because the mean of its divisors is an integer number (66312027217611).

Almost surely, 2132624054435221 is an apocalyptic number.

It is an amenable number.

132624054435221 is a deficient number, since it is larger than the sum of its proper divisors (1).

132624054435221 is an equidigital number, since it uses as much as digits as its factorization.

132624054435221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1382400, while the sum is 44.

The spelling of 132624054435221 in words is "one hundred thirty-two trillion, six hundred twenty-four billion, fifty-four million, four hundred thirty-five thousand, two hundred twenty-one".