Base | Representation |
---|---|
bin | 1100000011111110100000… |
… | …1110001000111001000101 |
3 | 1201221212201122102011221201 |
4 | 3000333220032020321011 |
5 | 3214243004234011201 |
6 | 44112405014342501 |
7 | 2536116060336331 |
oct | 300775016107105 |
9 | 51855648364851 |
10 | 13262460063301 |
11 | 4253639a54a19 |
12 | 15a242b05aa31 |
13 | 75284c2c0117 |
14 | 33bc995b27c1 |
15 | 17eec12eb801 |
hex | c0fe8388e45 |
13262460063301 has 2 divisors, whose sum is σ = 13262460063302. Its totient is φ = 13262460063300.
The previous prime is 13262460063211. The next prime is 13262460063323. The reversal of 13262460063301 is 10336006426231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13045279830625 + 217180232676 = 3611825^2 + 466026^2 .
It is a cyclic number.
It is not a de Polignac number, because 13262460063301 - 217 = 13262459932229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13262460063901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6631230031650 + 6631230031651.
It is an arithmetic number, because the mean of its divisors is an integer number (6631230031651).
Almost surely, 213262460063301 is an apocalyptic number.
It is an amenable number.
13262460063301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13262460063301 is an equidigital number, since it uses as much as digits as its factorization.
13262460063301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 37.
Adding to 13262460063301 its reverse (10336006426231), we get a palindrome (23598466489532).
The spelling of 13262460063301 in words is "thirteen trillion, two hundred sixty-two billion, four hundred sixty million, sixty-three thousand, three hundred one".
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