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132653513125517 is a prime number
BaseRepresentation
bin11110001010010111001101…
…100001110010111010001101
3122101200112220102002122001212
4132022113031201302322031
5114341343343330004032
61150044103241144205
736640620501134666
oct3612271541627215
9571615812078055
10132653513125517
11392a404798687a
1212a6518118b065
1359032322ca467
1424a867003a36d
1510509503d9bb2
hex78a5cd872e8d

132653513125517 has 2 divisors, whose sum is σ = 132653513125518. Its totient is φ = 132653513125516.

The previous prime is 132653513125481. The next prime is 132653513125633. The reversal of 132653513125517 is 715521315356231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130819929023716 + 1833584101801 = 11437654^2 + 1354099^2 .

It is an emirp because it is prime and its reverse (715521315356231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132653513125517 - 220 = 132653512076941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132653513125817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326756562758 + 66326756562759.

It is an arithmetic number, because the mean of its divisors is an integer number (66326756562759).

Almost surely, 2132653513125517 is an apocalyptic number.

It is an amenable number.

132653513125517 is a deficient number, since it is larger than the sum of its proper divisors (1).

132653513125517 is an equidigital number, since it uses as much as digits as its factorization.

132653513125517 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2835000, while the sum is 50.

The spelling of 132653513125517 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred thirteen million, one hundred twenty-five thousand, five hundred seventeen".