Base | Representation |
---|---|
bin | 11110001010010111001110… |
… | …001001100111011111101001 |
3 | 122101200112221010201222200122 |
4 | 132022113032021213133221 |
5 | 114341343404013031041 |
6 | 1150044104253013025 |
7 | 36640620655643261 |
oct | 3612271611473751 |
9 | 571615833658618 |
10 | 132653523564521 |
11 | 392a4052866853 |
12 | 12a65184784175 |
13 | 5903234513a9b |
14 | 24a86715967a1 |
15 | 105095129cc4b |
hex | 78a5ce2677e9 |
132653523564521 has 2 divisors, whose sum is σ = 132653523564522. Its totient is φ = 132653523564520.
The previous prime is 132653523564493. The next prime is 132653523564559. The reversal of 132653523564521 is 125465325356231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102954729448921 + 29698794115600 = 10146661^2 + 5449660^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132653523564521 is a prime.
It is not a weakly prime, because it can be changed into another prime (132653523564581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326761782260 + 66326761782261.
It is an arithmetic number, because the mean of its divisors is an integer number (66326761782261).
Almost surely, 2132653523564521 is an apocalyptic number.
It is an amenable number.
132653523564521 is a deficient number, since it is larger than the sum of its proper divisors (1).
132653523564521 is an equidigital number, since it uses as much as digits as its factorization.
132653523564521 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19440000, while the sum is 53.
The spelling of 132653523564521 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred twenty-three million, five hundred sixty-four thousand, five hundred twenty-one".
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