132654143711753 has 2 divisors, whose sum is σ = 132654143711754. Its totient is φ = 132654143711752.

The previous prime is 132654143711711. The next prime is 132654143711801. The reversal of 132654143711753 is 357117341456231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105065513521609 + 27588630190144 = 10250147^2 + 5252488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132654143711753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132654143711695 and 132654143711704.

It is not a weakly prime, because it can be changed into another prime (132654143741753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327071855876 + 66327071855877.

It is an arithmetic number, because the mean of its divisors is an integer number (66327071855877).

Almost surely, 2^{132654143711753} is an apocalyptic number.

It is an amenable number.

132654143711753 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654143711753 is an equidigital number, since it uses as much as digits as its factorization.

132654143711753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6350400, while the sum is 53.

The spelling of 132654143711753 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-three million, seven hundred eleven thousand, seven hundred fifty-three".