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132654144111061 is a prime number
BaseRepresentation
bin11110001010010111110011…
…001000110100000111010101
3122101200121112101102000111211
4132022113303020310013111
5114341401141343023221
61150044250021301421
736640642232335666
oct3612276310640725
9571617471360454
10132654144111061
11392a4341078631
1212a65318564871
135903302c547a1
1424a86cdb6b36d
15105098a9c86e1
hex78a5f32341d5

132654144111061 has 2 divisors, whose sum is σ = 132654144111062. Its totient is φ = 132654144111060.

The previous prime is 132654144111037. The next prime is 132654144111089. The reversal of 132654144111061 is 160111441456231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117561649482225 + 15092494628836 = 10842585^2 + 3884906^2 .

It is a cyclic number.

It is not a de Polignac number, because 132654144111061 - 213 = 132654144102869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132654144118061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072055530 + 66327072055531.

It is an arithmetic number, because the mean of its divisors is an integer number (66327072055531).

Almost surely, 2132654144111061 is an apocalyptic number.

It is an amenable number.

132654144111061 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654144111061 is an equidigital number, since it uses as much as digits as its factorization.

132654144111061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 40.

Adding to 132654144111061 its reverse (160111441456231), we get a palindrome (292765585567292).

The spelling of 132654144111061 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, one hundred eleven thousand, sixty-one".