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132654144171013 is a prime number
BaseRepresentation
bin11110001010010111110011…
…001001000010110000000101
3122101200121112101112001202021
4132022113303021002300011
5114341401141401433023
61150044250022443141
736640642233005533
oct3612276311026005
9571617471461667
10132654144171013
11392a4341109683
1212a653185934b1
135903302c75b6a
1424a86cdb85153
15105098a9db35d
hex78a5f3242c05

132654144171013 has 2 divisors, whose sum is σ = 132654144171014. Its totient is φ = 132654144171012.

The previous prime is 132654144170963. The next prime is 132654144171061. The reversal of 132654144171013 is 310171441456231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78549542901124 + 54104601269889 = 8862818^2 + 7355583^2 .

It is a cyclic number.

It is not a de Polignac number, because 132654144171013 - 237 = 132516705217541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132654144175013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072085506 + 66327072085507.

It is an arithmetic number, because the mean of its divisors is an integer number (66327072085507).

Almost surely, 2132654144171013 is an apocalyptic number.

It is an amenable number.

132654144171013 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654144171013 is an equidigital number, since it uses as much as digits as its factorization.

132654144171013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 43.

The spelling of 132654144171013 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, one hundred seventy-one thousand, thirteen".