Base | Representation |
---|---|
bin | 11110001010011000111000… |
… | …101110101011010001100111 |
3 | 122101200201112202100212100211 |
4 | 132022120320232223101213 |
5 | 114341411034241223411 |
6 | 1150045001530120251 |
7 | 36641013200355046 |
oct | 3612307056532147 |
9 | 571621482325324 |
10 | 132655311664231 |
11 | 392a4890132604 |
12 | 12a655a3580087 |
13 | 590345aac8355 |
14 | 24a87a0c5255d |
15 | 1050a08255221 |
hex | 78a638bab467 |
132655311664231 has 2 divisors, whose sum is σ = 132655311664232. Its totient is φ = 132655311664230.
The previous prime is 132655311664181. The next prime is 132655311664243. The reversal of 132655311664231 is 132466113556231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132655311664231 - 227 = 132655177446503 is a prime.
It is a super-3 number, since 3×1326553116642313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132655311667231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327655832115 + 66327655832116.
It is an arithmetic number, because the mean of its divisors is an integer number (66327655832116).
Almost surely, 2132655311664231 is an apocalyptic number.
132655311664231 is a deficient number, since it is larger than the sum of its proper divisors (1).
132655311664231 is an equidigital number, since it uses as much as digits as its factorization.
132655311664231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2332800, while the sum is 49.
The spelling of 132655311664231 in words is "one hundred thirty-two trillion, six hundred fifty-five billion, three hundred eleven million, six hundred sixty-four thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •