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132656135300341 is a prime number
BaseRepresentation
bin11110001010011001101001…
…110100100110010011110101
3122101200210200011011220200221
4132022121221310212103311
5114341414231114102331
61150045215351334341
736641042461223362
oct3612315164462365
9571623604156627
10132656135300341
11392a5173047604
1212a657933813b1
13590355c6356b3
1424a883c3b1469
151050a556ea711
hex78a669d264f5

132656135300341 has 2 divisors, whose sum is σ = 132656135300342. Its totient is φ = 132656135300340.

The previous prime is 132656135300327. The next prime is 132656135300407. The reversal of 132656135300341 is 143003531656231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104098066499716 + 28558068800625 = 10202846^2 + 5343975^2 .

It is a cyclic number.

It is not a de Polignac number, because 132656135300341 - 235 = 132621775561973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132656135300321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328067650170 + 66328067650171.

It is an arithmetic number, because the mean of its divisors is an integer number (66328067650171).

Almost surely, 2132656135300341 is an apocalyptic number.

It is an amenable number.

132656135300341 is a deficient number, since it is larger than the sum of its proper divisors (1).

132656135300341 is an equidigital number, since it uses as much as digits as its factorization.

132656135300341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 583200, while the sum is 43.

Adding to 132656135300341 its reverse (143003531656231), we get a palindrome (275659666956572).

The spelling of 132656135300341 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, one hundred thirty-five million, three hundred thousand, three hundred forty-one".