Base | Representation |
---|---|
bin | 11110001010011001110100… |
… | …110101101001000011000111 |
3 | 122101200211011000221212211112 |
4 | 132022121310311221003013 |
5 | 114341420120422414304 |
6 | 1150045245552555235 |
7 | 36641050164206234 |
oct | 3612316465510307 |
9 | 571624130855745 |
10 | 132656320123079 |
11 | 392a5258403675 |
12 | 12a65825252b1b |
13 | 590358ba0776c |
14 | 24a8858b6278b |
15 | 1050a66a57b6e |
hex | 78a674d690c7 |
132656320123079 has 2 divisors, whose sum is σ = 132656320123080. Its totient is φ = 132656320123078.
The previous prime is 132656320123043. The next prime is 132656320123133. The reversal of 132656320123079 is 970321023656231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132656320123079 - 212 = 132656320118983 is a prime.
It is a super-3 number, since 3×1326563201230793 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132656320123039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328160061539 + 66328160061540.
It is an arithmetic number, because the mean of its divisors is an integer number (66328160061540).
Almost surely, 2132656320123079 is an apocalyptic number.
132656320123079 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656320123079 is an equidigital number, since it uses as much as digits as its factorization.
132656320123079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 50.
The spelling of 132656320123079 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred twenty million, one hundred twenty-three thousand, seventy-nine".
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