Base | Representation |
---|---|
bin | 11110001010011001110101… |
… | …100100101110011110000011 |
3 | 122101200211011220011222012122 |
4 | 132022121311210232132003 |
5 | 114341420132102403201 |
6 | 1150045251113314455 |
7 | 36641050404134462 |
oct | 3612316544563603 |
9 | 571624156158178 |
10 | 132656332466051 |
11 | 392a5264374079 |
12 | 12a65829405a2b |
13 | 59035914398b4 |
14 | 24a885a6569d9 |
15 | 1050a67b94e1b |
hex | 78a67592e783 |
132656332466051 has 2 divisors, whose sum is σ = 132656332466052. Its totient is φ = 132656332466050.
The previous prime is 132656332466039. The next prime is 132656332466093. The reversal of 132656332466051 is 150664233656231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132656332466051 - 230 = 132655258724227 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 132656332465984 and 132656332466002.
It is not a weakly prime, because it can be changed into another prime (132656332463051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328166233025 + 66328166233026.
It is an arithmetic number, because the mean of its divisors is an integer number (66328166233026).
Almost surely, 2132656332466051 is an apocalyptic number.
132656332466051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656332466051 is an equidigital number, since it uses as much as digits as its factorization.
132656332466051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13996800, while the sum is 53.
The spelling of 132656332466051 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred thirty-two million, four hundred sixty-six thousand, fifty-one".
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