Base | Representation |
---|---|
bin | 11110001010011001110110… |
… | …010000111101100001110111 |
3 | 122101200211012201000002221212 |
4 | 132022121312100331201313 |
5 | 114341420143034441241 |
6 | 1150045252210032035 |
7 | 36641050604532224 |
oct | 3612316620754167 |
9 | 571624181002855 |
10 | 132656344062071 |
11 | 392a526a974365 |
12 | 12a6583127861b |
13 | 5903593969a4b |
14 | 24a885bdd494b |
15 | 1050a68bd5beb |
hex | 78a67643d877 |
132656344062071 has 2 divisors, whose sum is σ = 132656344062072. Its totient is φ = 132656344062070.
The previous prime is 132656344062023. The next prime is 132656344062079. The reversal of 132656344062071 is 170260443656231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132656344062071 - 242 = 128258297550967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132656344062079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328172031035 + 66328172031036.
It is an arithmetic number, because the mean of its divisors is an integer number (66328172031036).
Almost surely, 2132656344062071 is an apocalyptic number.
132656344062071 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656344062071 is an equidigital number, since it uses as much as digits as its factorization.
132656344062071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4354560, while the sum is 50.
The spelling of 132656344062071 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred forty-four million, sixty-two thousand, seventy-one".
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