Base | Representation |
---|---|
bin | 11110001010011010000001… |
… | …000011010111011001011111 |
3 | 122101200211200022120010010212 |
4 | 132022122001003113121133 |
5 | 114341421030403004031 |
6 | 1150045322153123035 |
7 | 36641055233063222 |
oct | 3612320103273137 |
9 | 571624608503125 |
10 | 132656525047391 |
11 | 392a535304a304 |
12 | 12a658819b947b |
13 | 59035c22c7257 |
14 | 24a88780675b9 |
15 | 1050a79a3612b |
hex | 78a6810d765f |
132656525047391 has 2 divisors, whose sum is σ = 132656525047392. Its totient is φ = 132656525047390.
The previous prime is 132656525047301. The next prime is 132656525047411. The reversal of 132656525047391 is 193740525656231.
It is a strong prime.
It is an emirp because it is prime and its reverse (193740525656231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132656525047391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132656525047391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132656525047301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328262523695 + 66328262523696.
It is an arithmetic number, because the mean of its divisors is an integer number (66328262523696).
Almost surely, 2132656525047391 is an apocalyptic number.
132656525047391 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656525047391 is an equidigital number, since it uses as much as digits as its factorization.
132656525047391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824000, while the sum is 59.
The spelling of 132656525047391 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, five hundred twenty-five million, forty-seven thousand, three hundred ninety-one".
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