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132656525055553 is a prime number
BaseRepresentation
bin11110001010011010000001…
…000011011001011001000001
3122101200211200022120112100011
4132022122001003121121001
5114341421030403234203
61150045322153224521
736641055233126062
oct3612320103313101
9571624608515304
10132656525055553
11392a5353055454
1212a65881a02141
1359035c22cab95
1424a887806a569
151050a79a3876d
hex78a6810d9641

132656525055553 has 2 divisors, whose sum is σ = 132656525055554. Its totient is φ = 132656525055552.

The previous prime is 132656525055541. The next prime is 132656525055583. The reversal of 132656525055553 is 355550525656231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132101392770369 + 555132285184 = 11493537^2 + 745072^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132656525055553 is a prime.

It is a super-2 number, since 2×1326565250555532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132656525055583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328262527776 + 66328262527777.

It is an arithmetic number, because the mean of its divisors is an integer number (66328262527777).

Almost surely, 2132656525055553 is an apocalyptic number.

It is an amenable number.

132656525055553 is a deficient number, since it is larger than the sum of its proper divisors (1).

132656525055553 is an equidigital number, since it uses as much as digits as its factorization.

132656525055553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 101250000, while the sum is 58.

The spelling of 132656525055553 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, five hundred twenty-five million, fifty-five thousand, five hundred fifty-three".