Base | Representation |
---|---|
bin | 11110001010011010000001… |
… | …000011011001011001011111 |
3 | 122101200211200022120112101021 |
4 | 132022122001003121121133 |
5 | 114341421030403234313 |
6 | 1150045322153225011 |
7 | 36641055233126134 |
oct | 3612320103313137 |
9 | 571624608515337 |
10 | 132656525055583 |
11 | 392a5353055481 |
12 | 12a65881a02167 |
13 | 59035c22cabb9 |
14 | 24a887806a58b |
15 | 1050a79a3878d |
hex | 78a6810d965f |
132656525055583 has 2 divisors, whose sum is σ = 132656525055584. Its totient is φ = 132656525055582.
The previous prime is 132656525055553. The next prime is 132656525055611. The reversal of 132656525055583 is 385550525656231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132656525055583 - 213 = 132656525047391 is a prime.
It is a super-2 number, since 2×1326565250555832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132656525055553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328262527791 + 66328262527792.
It is an arithmetic number, because the mean of its divisors is an integer number (66328262527792).
Almost surely, 2132656525055583 is an apocalyptic number.
132656525055583 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656525055583 is an equidigital number, since it uses as much as digits as its factorization.
132656525055583 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000000, while the sum is 61.
The spelling of 132656525055583 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, five hundred twenty-five million, fifty-five thousand, five hundred eighty-three".
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