Base | Representation |
---|---|
bin | 11110001010011110100111… |
… | …010101001100111011000111 |
3 | 122101201022102101201201000101 |
4 | 132022132213111030323013 |
5 | 114342011133312141313 |
6 | 1150051500122024531 |
7 | 36641321463305635 |
oct | 3612364725147307 |
9 | 571638371651011 |
10 | 132661462224583 |
11 | 392a7456a48636 |
12 | 12a6681b348147 |
13 | 5903bcb12b086 |
14 | 24a8bc5a54355 |
15 | 1050c681cd5dd |
hex | 78a7a754cec7 |
132661462224583 has 2 divisors, whose sum is σ = 132661462224584. Its totient is φ = 132661462224582.
The previous prime is 132661462224569. The next prime is 132661462224673. The reversal of 132661462224583 is 385422264166231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132661462224583 is a prime.
It is a super-3 number, since 3×1326614622245833 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132661462224283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66330731112291 + 66330731112292.
It is an arithmetic number, because the mean of its divisors is an integer number (66330731112292).
Almost surely, 2132661462224583 is an apocalyptic number.
132661462224583 is a deficient number, since it is larger than the sum of its proper divisors (1).
132661462224583 is an equidigital number, since it uses as much as digits as its factorization.
132661462224583 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19906560, while the sum is 55.
The spelling of 132661462224583 in words is "one hundred thirty-two trillion, six hundred sixty-one billion, four hundred sixty-two million, two hundred twenty-four thousand, five hundred eighty-three".
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