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132661653560143 is a prime number
BaseRepresentation
bin11110001010011110110010…
…101111000101101101001111
3122101201022220201202120001121
4132022132302233011231033
5114342012031302411033
61150051531115021411
736641326305525361
oct3612366257055517
9571638821676047
10132661653560143
11392a7544a528a4
1212a6687343a867
135903c2b970696
1424a8c0321cd31
151050c79dc562d
hex78a7b2bc5b4f

132661653560143 has 2 divisors, whose sum is σ = 132661653560144. Its totient is φ = 132661653560142.

The previous prime is 132661653560077. The next prime is 132661653560197. The reversal of 132661653560143 is 341065356166231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132661653560143 is a prime.

It is a super-2 number, since 2×1326616535601432 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132661653569143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66330826780071 + 66330826780072.

It is an arithmetic number, because the mean of its divisors is an integer number (66330826780072).

Almost surely, 2132661653560143 is an apocalyptic number.

132661653560143 is a deficient number, since it is larger than the sum of its proper divisors (1).

132661653560143 is an equidigital number, since it uses as much as digits as its factorization.

132661653560143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6998400, while the sum is 52.

The spelling of 132661653560143 in words is "one hundred thirty-two trillion, six hundred sixty-one billion, six hundred fifty-three million, five hundred sixty thousand, one hundred forty-three".