Base | Representation |
---|---|
bin | 111101110001111100… |
… | …0001101001111010111 |
3 | 110200110011010010010011 |
4 | 1323203320031033113 |
5 | 4133203034244312 |
6 | 140540533141051 |
7 | 12404511635056 |
oct | 1734370151727 |
9 | 420404103104 |
10 | 132672181207 |
11 | 512a1a95455 |
12 | 2186778a787 |
13 | c68469b047 |
14 | 65c833a39d |
15 | 36b7750da7 |
hex | 1ee3e0d3d7 |
132672181207 has 2 divisors, whose sum is σ = 132672181208. Its totient is φ = 132672181206.
The previous prime is 132672181193. The next prime is 132672181217. The reversal of 132672181207 is 702181276231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132672181207 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132672181207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132672181217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66336090603 + 66336090604.
It is an arithmetic number, because the mean of its divisors is an integer number (66336090604).
Almost surely, 2132672181207 is an apocalyptic number.
132672181207 is a deficient number, since it is larger than the sum of its proper divisors (1).
132672181207 is an equidigital number, since it uses as much as digits as its factorization.
132672181207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56448, while the sum is 40.
The spelling of 132672181207 in words is "one hundred thirty-two billion, six hundred seventy-two million, one hundred eighty-one thousand, two hundred seven".
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